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-X^2-9X+6=0
We add all the numbers together, and all the variables
-1X^2-9X+6=0
a = -1; b = -9; c = +6;
Δ = b2-4ac
Δ = -92-4·(-1)·6
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{105}}{2*-1}=\frac{9-\sqrt{105}}{-2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{105}}{2*-1}=\frac{9+\sqrt{105}}{-2} $
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